Shearing
$Rysunek$
Oblique section location: x = $x$ m
Transversal force: Q = $Q$ kN
Profile dimmentions: b = $b$ cm
ho = h - a = $h$ - $a$ = $h0$ cm
$Tekst_Beta$ bs = $BetaS$
Stirrups: $Tekst_Strzem$
Steel resistance: Ras = 0,8 Ra = $Ras$ MPa
Rao = 0,8 Ra = $Rao$ MPa
Force carried by stirrups: Fs Ras = $LCiec$×$Fs$×$Ras$×10-1 = $RasFs$ kN
Stirrups spacing: s = $s_mm$ mm
(*Rozciag Analysis concrete resistance for tending element:
cs = 1 - 0,2 N / Rbz b ho = 1 - 0,2×$N$ / ($Rbz$×$b$×$h0$×10-1) = $k$
it is accepted cs = $kS$.
Rb = $Rb$×$kS$ = $Rb_$ MPa
Rbz = $Rbz$×$kS$ = $Rbz_$ MPa
*)(*W41 Profile not accomplied a condition (41):
Q = $Q$ > $Q41$ = 0,25×$Rb_$×$b$×$h0$×10-1 = 0,25 Rb b ho
*)(*W42 It is accomplied a condition (42):
Q = $Q$ Ł $Q42$ = 0,75×$Rbz_$×$b$×$h0$×10-1 = 0,75 Rbz b ho
It can by not to check a oblique section capacity.
*)(*Sprawdzenie Stirrups capacity for unit of length:
qs = Ras Fs / s = $RasFs$ / $s$ = $qs$ kN/m
Oblique section projection length: (*SilaSkup cs = $cs$ m *|*
(*SciskUkos $W45u$ = $cs$ m*|* $W45$ = $cs$ m*)*)
Transversal force carried by stirrups and concrete:
$W47$
Oblique section capacity condition:
(*ODG Q = $War48$ = $Qsb$ + $Qo$(*RozciagUkos + ( $M$ - $SUMs$ - $SUMo$ ) ×$tgv$ / $z$*) = Qsb + S Rao Fo sin ao(*RozciagUkos + ( M - S Ras Fs zsi - S Rao Fo zoi ) tg u / z *)
*|* Q = $War47$ =(*RozciagUkos $Qsb$ + ( $M$ - $SUMs$ ) ×$tgv$ / $z$ = Qsb + ( M - S Ras Fs zsi ) tg u / z*|* Qsb*)
*)*)
misiak10-1985