SYMETRIA CP W UKŁADZIE NEUTRALNYCH MEZONÓW.pdf

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Wojciech Wislicki, 20/1/2006
SYMETRIA CP W UKADZIE NEUTRALNYCH
MEZONÓW K
K 0 K 0 jest dwustanowym ukadem kwantowym, rozpadajacym sie w
oddziaywaniach sabych.
Uznanie dla badaczy zyki K 0 :
1980, Nagroda Nobla dla J.W. Cronina i V.L. Fitcha za odkrycie
naruszenia CP przez mieszanie stanów,
2005, Nagroda EPS dla H. Wahla i NA31 za wkad w odkrycie
bezposredniego naruszenia CP .
114511692.002.png
Komitet Noblowski z 12/10/1980:
The Royal Swedish Academy of Sciences has decided to award the 1980
Nobel Prize in Physics to Professor James W. Cronin, University of Chicago,
USA and Professor Val L. Fitch, Princeton University, USA, for the
discovery of violations of fundamental symmetry principles in the decay of
neutral K-mesons.
Symmetries play a great role in many sciences and also in many other areas.
This year's Nobel Prize in Physics is awarded for an unexpected discovery
in an experiment devoted to a critical scrutiny of the validity of three
related symmetry principles. These are of real importance to the
formulation of fundamental laws of Nature.
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EPS (za CERN Courier, nr 7, 2005):
The 2005 prizes of the High Energy and Particle Physics (HEPP) Division of
the European Physical Society (EPS) were awarded on 25 July at the start
of the plenary sessions for the International Europhysics Conference on
High Energy Physics, HEP2005, in Lisbon.
The 2005 EPS-HEPP Prize was awarded jointly to Heinrich Wahl of CERN,
for his outstanding leadership of challenging experiments on CP Violation , and
to CERN's NA31 Collaboration, which showed for the rst time direct CP
Violation in the decays of neutral K mesons . Wahl, who retired in 2003, had a
long association with CP-violation experiments from his arrival at CERN in
1969. He was spokesman of NA31 and a major proponent of its successor,
NA48.
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Uwagi wstepne
C : Q
!
-Q
P : ~r
!
-~r
Kombinacja CP zamienia materie z antymateria, np.
CP : e L
!
e R
CP : e R
!
e L
114511692.005.png
O ile wiemy, tylko oddziaywania sabe naruszaja C i P , ale za to
maksymalnie:
W sprzega sie do e L , ale nie do C(e L ) = e L , ani P(e L ) = e R
Natomiast CP zachowane jest dosc dobrze:
W sprzega sie zarówno do e L , jak do CP(e L ) = e R
114511692.001.png
Zgłoś jeśli naruszono regulamin