SW2K_F.RTF

Capacité du treillissement.

xa = $xa$;  xb = $xb$.

(*X Treillis perpendiculaire à l’axe X:

              Q = 1,2 V = 1,2×$1.2.1$ = $2.20.1$ kN     

              Q ³ 0,012 A fd = 0,012×$2.21$×$2.22$×10-1 = $2.23$ kN

              Soit Q = $2.1.1$ kN

                            NK = Q / (n sin a) = $2.1.1$×$3.1.1$ / $3.2.1$ / $3.4.1$ = $3.3.1$ kN

                            NR = A fd = $3.4$×$0.3$×10-1 = $3.5$ kN

                            lK = lK / iK = $3.1.1$ / $3.6$ = $3.8.1$

                            $W38$

                            K = lK / lp = $3.8.1$ / $3.7$ = $3.9.1$        Þ       j = $3.10.1$

                                          $W39x$

                            NK = $W32x$×10-1 = A y fd

*)(*Y Treillis perpendiculaire à l’axe Y:

              Q = 1,2 V = 1,2×$1.2.2$ = $2.20.2$ kN     

              Q ³ 0,012 A fd = 0,012×$2.21$×$2.22$×10-1 = $2.23$ kN

              Soit  Q = $2.1.2$ kN

                            NK = Q / (n sin a) = $2.1.2$×$3.1.2$ / $3.2.2$ / $3.4.2$ = $3.3.2$ kN

                            NR = A fd = $3.4$×$0.3$×10-1 = $3.5$ kN

                            lK = lK / iK = $3.1.2$ / $3.6$ = $3.8.2$

                            $W38$

                            K = lK / lp = $3.8.2$ / $3.7$ = $3.9.2$        Þ              j = $3.10.2$

                                          $W39y$

                            NK = $W32y$×10-1 = A y fd

*)