p19_020.pdf
(
64 KB
)
Pobierz
Chapter 19 - 19.20
20. (a) We use
ρ
=
m/V
and ∆
ρ
=∆(
m/V
)=
m
∆(1
/V
)
m
∆
V/V
2
=
−
ρ
(∆
V/V
)=
−
3
ρ
(∆
L/L
)
.
The percent change in density is
∆
ρ
ρ
=
−
L
=
−
3(0
.
23%)=
−
0
.
69%
.
(b) Since
α
=∆
L/
(
L
∆
T
)=0
.
23
×
10
−
2
/
(100
◦
C
−
0
.
0
◦
C) = 23
×
10
−
6
/
C
◦
,
the metal is aluminum
(using Table 19-2).
−
3
∆
L
Plik z chomika:
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Inne pliki z tego folderu:
p19_102.pdf
(66 KB)
P19_002.PDF
(57 KB)
P19_001.PDF
(63 KB)
P19_003.PDF
(70 KB)
P19_005.PDF
(65 KB)
Inne foldery tego chomika:
chap01
chap02
chap03
chap04
chap05
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