p19_102.pdf
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Pobierz
Chapter 19 - 19.102
10
−
7
W
where we have used the fact that the surface area of the cube is
A
=6
A
face
=6
2
.
0
T
4
=
3
.
8
×
×
10
−
5
m
2
=
2
.
4
×
10
−
9
m
2
.
102. Using Eq. 19-40 with
T
= 323 K and
T
env
= 293 K, we find
P
net
=
σεA
T
env
−
−
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p19_102.pdf
(66 KB)
P19_002.PDF
(57 KB)
P19_001.PDF
(63 KB)
P19_003.PDF
(70 KB)
P19_005.PDF
(65 KB)
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