P22_034.PDF
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Chapter 22 - 22.34
34. Let the two charges be
q
1
and
q
2
.Then
q
1
+
q
2
=
Q
=5
.
0
×
10
−
5
C. We use Eq. 22-1:
1
.
0N=
8
.
99
×
10
9
N
·
m
2
C
2
q
1
q
2
.
(2
.
0m)
2
q
1
and solve for
q
1
using the quadratic formula. The two roots obtained are the
values of
q
1
and
q
2
, since it does not matter which is which. We get 1
.
2
−
×
10
−
5
Cand3
.
8
×
10
−
5
C.
We substitute
q
2
=
Q
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